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	<title>Comments on: The Bokeh Files featuring the Leica M9 &amp; Olympus E-P2</title>
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	<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/</link>
	<description>Digital Camera and Lens Reviews for Enthusiasts</description>
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		<title>By: Dominiek</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-103112</link>
		<dc:creator>Dominiek</dc:creator>
		<pubDate>Wed, 30 Nov 2011 22:49:33 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-103112</guid>
		<description>Hello Steve,

I recently bought me an adapter for using my fathers old lenses (Leica R 35,50,80,180 and 250mm) on my Lumix G3, and I was somewhat disappointed on bokeh results.  By help of your explanation above, I understand why, and I know how to work on this.   Thanks for this.  

I have an other question that is related to this kind of hardware setup:  Every lens produces a circular picture that is projected on a rectangular film or sensor inside the camera.  When combining full frame lenses with full frame camera, one can calculate that +/- 59% of the circle area is projected on the rectangle area.  The remaining 41% of light is absorbed by black paint inside the camera as much as possible.    In a configuration of a full frame lens with a micro 4/3 camera, one can calculate that only +/-15% of the light hits the sensor, and 85% needs to be absorbed!!!.  Knowing that there is no paint yet that fully absorbs light, I wander if there is no visible bad influence of this reflecting light that is present in a quantity out of proportion inside the camera?  I am wandering also if micro 4/3 camera producers design the full larger zone around the sensor for an optimal light absorbtion?  It was these scientific facts that made me hesitate longtime for buying an adaptor.  What is your experience or opinion in these?

Thanks,
Dominiek</description>
		<content:encoded><![CDATA[<p>Hello Steve,</p>
<p>I recently bought me an adapter for using my fathers old lenses (Leica R 35,50,80,180 and 250mm) on my Lumix G3, and I was somewhat disappointed on bokeh results.  By help of your explanation above, I understand why, and I know how to work on this.   Thanks for this.  </p>
<p>I have an other question that is related to this kind of hardware setup:  Every lens produces a circular picture that is projected on a rectangular film or sensor inside the camera.  When combining full frame lenses with full frame camera, one can calculate that +/- 59% of the circle area is projected on the rectangle area.  The remaining 41% of light is absorbed by black paint inside the camera as much as possible.    In a configuration of a full frame lens with a micro 4/3 camera, one can calculate that only +/-15% of the light hits the sensor, and 85% needs to be absorbed!!!.  Knowing that there is no paint yet that fully absorbs light, I wander if there is no visible bad influence of this reflecting light that is present in a quantity out of proportion inside the camera?  I am wandering also if micro 4/3 camera producers design the full larger zone around the sensor for an optimal light absorbtion?  It was these scientific facts that made me hesitate longtime for buying an adaptor.  What is your experience or opinion in these?</p>
<p>Thanks,<br />
Dominiek</p>
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		<title>By: FunkyRider</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-75475</link>
		<dc:creator>FunkyRider</dc:creator>
		<pubDate>Mon, 19 Sep 2011 04:36:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-75475</guid>
		<description>Yes the lens gathers the same amount of light no matter where it is mounted on, BUT, the sensor collects different amount of light. Full frame sensor uses all light collected by the lens (forget about the area between sensor rectangle and image circle for now), but a 3/4 sensor only picks up 1/4 amount of photos! That means the signal has to be amplified 4 timers to get the correct ISO equivalent exposure. That&#039;s another effect of larger sensors: higher signal to noise ratio. So in amount of light&#039;s term, 50 F2 on 3/4 does equal to 100 F4 on full frame: The fact that the smaller 3/4 sensor only uses a quarter of light makes it an F4 equivalent, just like a tele converter</description>
		<content:encoded><![CDATA[<p>Yes the lens gathers the same amount of light no matter where it is mounted on, BUT, the sensor collects different amount of light. Full frame sensor uses all light collected by the lens (forget about the area between sensor rectangle and image circle for now), but a 3/4 sensor only picks up 1/4 amount of photos! That means the signal has to be amplified 4 timers to get the correct ISO equivalent exposure. That&#8217;s another effect of larger sensors: higher signal to noise ratio. So in amount of light&#8217;s term, 50 F2 on 3/4 does equal to 100 F4 on full frame: The fact that the smaller 3/4 sensor only uses a quarter of light makes it an F4 equivalent, just like a tele converter</p>
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		<title>By: tesilab</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-60151</link>
		<dc:creator>tesilab</dc:creator>
		<pubDate>Wed, 06 Jul 2011 17:14:35 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-60151</guid>
		<description>While the information is extremely helpful, you could make it a lot less confusing by rewriting statements like this one:

&quot;If you slap a 25mm F2 lens on a m4/3 camera it will be like shooting with a 50mm in regards to focal length, but your depth of field will be that of a 25mm lens at F2, not a 50mm lens at F2.&quot;

Like this:

&quot;For 35mm film, or equivalent sensor size (full-frame), a 50mm lens has a (diagonal) angle of view of roughly 47 degrees. If you slap a 25mm f2 lens on a m4/3 camera, the angle of view would be nearly equivalent to full-frame 50mm, but the depth of field remains a function of the actual focal length of the lens at f2, and not the angle of view.&quot;

Similarly this line would need to be rewritten:

&quot;The sensor size turns the lens into a 50mm focal length but you are still shooting with a 25mm lens...&quot;

To be more like this:

&quot;While the sensor size (crop factor) gives you the equivalent field of view of a 50mm lens on a full-frame camera, you are still shooting with a 25mm lens&quot;</description>
		<content:encoded><![CDATA[<p>While the information is extremely helpful, you could make it a lot less confusing by rewriting statements like this one:</p>
<p>&#8220;If you slap a 25mm F2 lens on a m4/3 camera it will be like shooting with a 50mm in regards to focal length, but your depth of field will be that of a 25mm lens at F2, not a 50mm lens at F2.&#8221;</p>
<p>Like this:</p>
<p>&#8220;For 35mm film, or equivalent sensor size (full-frame), a 50mm lens has a (diagonal) angle of view of roughly 47 degrees. If you slap a 25mm f2 lens on a m4/3 camera, the angle of view would be nearly equivalent to full-frame 50mm, but the depth of field remains a function of the actual focal length of the lens at f2, and not the angle of view.&#8221;</p>
<p>Similarly this line would need to be rewritten:</p>
<p>&#8220;The sensor size turns the lens into a 50mm focal length but you are still shooting with a 25mm lens&#8230;&#8221;</p>
<p>To be more like this:</p>
<p>&#8220;While the sensor size (crop factor) gives you the equivalent field of view of a 50mm lens on a full-frame camera, you are still shooting with a 25mm lens&#8221;</p>
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		<title>By: Steve Huff</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-35920</link>
		<dc:creator>Steve Huff</dc:creator>
		<pubDate>Thu, 17 Feb 2011 16:14:24 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-35920</guid>
		<description>Thanks! Yea, you found an old one!</description>
		<content:encoded><![CDATA[<p>Thanks! Yea, you found an old one!</p>
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		<title>By: azx1</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-35887</link>
		<dc:creator>azx1</dc:creator>
		<pubDate>Thu, 17 Feb 2011 09:38:54 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-35887</guid>
		<description>I&#039;m constantly amazed when I search for really strange things in the pursuit of learning more about photography, I indelibly arrive back at your site for some weird ass comparisons that are completely useful.

Thanks Steve.</description>
		<content:encoded><![CDATA[<p>I&#8217;m constantly amazed when I search for really strange things in the pursuit of learning more about photography, I indelibly arrive back at your site for some weird ass comparisons that are completely useful.</p>
<p>Thanks Steve.</p>
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		<title>By: Jeff</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-8112</link>
		<dc:creator>Jeff</dc:creator>
		<pubDate>Mon, 24 May 2010 13:40:56 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-8112</guid>
		<description>Bob:
Exposure = amount of light delivered to the receiving medium  (freq. measured in lux seconds)
lux second = 1lumen / square meter * seconds (exposure time)
      
Please note that 1 lux is a RATIO and as such is independent of TOTAL SURFACE AREA.
It appears that you have confused PIXEL size with SENSOR size and signal to noise ratio with exposure value.  For the sake of clarity it needs to be established that they are independent concepts.

If I use an f2 lens on an imaging device and take an image of a uniformly lit white surface, when I calculate the desired exposure value when shooting at f2 1/100&quot; that is what I get - at ANY POINT within the image circle (ignoring vignetting problems for the sake of this discussion).  Cropping the sensor IS NOT the same as using an extension tube or teleconverter because the total size of the image circle remains the same and therefore the intensity of light at any given point in that circle is not affected.

What you are probably trying to conceptualize is more of an argument related to pixel size.  If all other things are equal (microlens spacing, efficiency and transmissivity, photodiode sensitivity and other circuitry) a sensor with larger PIXELS (completely independent of total sensor size) that sees the same intensity of light as a a sensor with smaller pixels will indeed collect more photons PER PIXEL (because those pixels cover a wider area).  At the pixel level, we are now talking about a TOTAL # photons and not just a ratio.  
To restate: Because the light INTENSITY is uniform, a larger PIXEL will be impacted by more photons than the small pixel.  With more photons being &quot;counted&quot; by the larger pixel, the signal to noise ratio may be higher (assuming all other things being equal including ideal scalability it WILL be higher).

You are correct in stating that each sensor has the gain set for it - the manufacturers take into account the signal-to-noise ratio as well as the &quot;well capacity&quot; and the sensor&#039;s response profile when determining the amount of gain to apply to the sensor (i.e. how little noise vs how easy to blow the highlights?).  

The argument that you make is related to PIXEL size and not directly to sensor size (compare Nikon D3X vs D3s ISO performance) - furthermore, when you shoot a Nikon D3x in crop mode you will notice that aperture/shutter speed/ISO do NOT change to maintain the same exposure for the &#039;cropped&#039; area (yes, that means that even behind the scenes the sensor GAIN does NOT change).

Sorry about the length of the pose but I hope this helps - more knowledge is always better IMO.

Steve:  Thanks for your work in providing this great comparison for those of us who are truly interested in the topic you present (DOF comparison) and discussion you provide.  

Cheers.</description>
		<content:encoded><![CDATA[<p>Bob:<br />
Exposure = amount of light delivered to the receiving medium  (freq. measured in lux seconds)<br />
lux second = 1lumen / square meter * seconds (exposure time)</p>
<p>Please note that 1 lux is a RATIO and as such is independent of TOTAL SURFACE AREA.<br />
It appears that you have confused PIXEL size with SENSOR size and signal to noise ratio with exposure value.  For the sake of clarity it needs to be established that they are independent concepts.</p>
<p>If I use an f2 lens on an imaging device and take an image of a uniformly lit white surface, when I calculate the desired exposure value when shooting at f2 1/100&#8243; that is what I get &#8211; at ANY POINT within the image circle (ignoring vignetting problems for the sake of this discussion).  Cropping the sensor IS NOT the same as using an extension tube or teleconverter because the total size of the image circle remains the same and therefore the intensity of light at any given point in that circle is not affected.</p>
<p>What you are probably trying to conceptualize is more of an argument related to pixel size.  If all other things are equal (microlens spacing, efficiency and transmissivity, photodiode sensitivity and other circuitry) a sensor with larger PIXELS (completely independent of total sensor size) that sees the same intensity of light as a a sensor with smaller pixels will indeed collect more photons PER PIXEL (because those pixels cover a wider area).  At the pixel level, we are now talking about a TOTAL # photons and not just a ratio.<br />
To restate: Because the light INTENSITY is uniform, a larger PIXEL will be impacted by more photons than the small pixel.  With more photons being &#8220;counted&#8221; by the larger pixel, the signal to noise ratio may be higher (assuming all other things being equal including ideal scalability it WILL be higher).</p>
<p>You are correct in stating that each sensor has the gain set for it &#8211; the manufacturers take into account the signal-to-noise ratio as well as the &#8220;well capacity&#8221; and the sensor&#8217;s response profile when determining the amount of gain to apply to the sensor (i.e. how little noise vs how easy to blow the highlights?).  </p>
<p>The argument that you make is related to PIXEL size and not directly to sensor size (compare Nikon D3X vs D3s ISO performance) &#8211; furthermore, when you shoot a Nikon D3x in crop mode you will notice that aperture/shutter speed/ISO do NOT change to maintain the same exposure for the &#8216;cropped&#8217; area (yes, that means that even behind the scenes the sensor GAIN does NOT change).</p>
<p>Sorry about the length of the pose but I hope this helps &#8211; more knowledge is always better IMO.</p>
<p>Steve:  Thanks for your work in providing this great comparison for those of us who are truly interested in the topic you present (DOF comparison) and discussion you provide.  </p>
<p>Cheers.</p>
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		<title>By: NOKTOR f/0.95 50mm Lens - Want! - MacTalk Forums</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-4954</link>
		<dc:creator>NOKTOR f/0.95 50mm Lens - Want! - MacTalk Forums</dc:creator>
		<pubDate>Wed, 31 Mar 2010 10:36:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-4954</guid>
		<description>[...] apparent focal length. Have a look here, he explains it with photos a little better than I can.  Testing Lens Bokeh on Full Frame and Micro 4/3 cameras &#124; STEVE HUFF PHOTOS     __________________ [...]</description>
		<content:encoded><![CDATA[<p>[...] apparent focal length. Have a look here, he explains it with photos a little better than I can.  Testing Lens Bokeh on Full Frame and Micro 4/3 cameras | STEVE HUFF PHOTOS     __________________ [...]</p>
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		<title>By: bob</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-4147</link>
		<dc:creator>bob</dc:creator>
		<pubDate>Tue, 16 Mar 2010 00:08:21 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-4147</guid>
		<description>Here&#039;s the film analogy.  Take a picture with 35mm film.  now use the exact same camera, exact same lens, but put 17mm film in it (cut a block of film half size in each direction and tape in on a piece of paper and stick it in the back of the camera.)  Ok.. well you might as well just take the picture with the 35mm film (it&#039;s easier) take the film in the dark room and then cut the negative down.  It&#039;s the same either way.  That&#039;s what a smaller sensor is on the same lens.  It&#039;s just a smaller sensor... on the same lens, at the same focal plane.  That&#039;s less light.</description>
		<content:encoded><![CDATA[<p>Here&#8217;s the film analogy.  Take a picture with 35mm film.  now use the exact same camera, exact same lens, but put 17mm film in it (cut a block of film half size in each direction and tape in on a piece of paper and stick it in the back of the camera.)  Ok.. well you might as well just take the picture with the 35mm film (it&#8217;s easier) take the film in the dark room and then cut the negative down.  It&#8217;s the same either way.  That&#8217;s what a smaller sensor is on the same lens.  It&#8217;s just a smaller sensor&#8230; on the same lens, at the same focal plane.  That&#8217;s less light.</p>
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		<title>By: bob</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-4145</link>
		<dc:creator>bob</dc:creator>
		<pubDate>Tue, 16 Mar 2010 00:01:30 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-4145</guid>
		<description>Ok.. I&#039;m back (sorry :)).  Jerry, yes you will get the same exposure with the same ISO and settings.  Of course.  That&#039;s because ISO in a digital calibrated for a particular camera to produce the right exposure at the right ISO.  The sunny 16 rule should always work.  ISO 100 **IS DEFINED** for any camera as WHATEVER sensor gain makes sunny 16 work for that camera.  That doesn&#039;t mean it uses the same amount of light from one camera to another.  That just means it&#039;s the gain correction needed to compensate for whatever amount light sunny 16 happens to be on that camera. That IS ISO 100.  In a cropped camera that happens to be a higher gain, because there is less light.  And thus it happens to produce more noise too.    I don&#039;t care what argument you make, you can&#039;t get around the fact, that the focal plane is where it is (unless you mess up infinity focus); the image size on that plane is what it is, ALWAYS for any given lens.  You either accept the whole image and all the light in it, or you crop that image and only accept part of it and part of the light in it.  Nobody has answered me, where did the light from the rest of the image go?  

Light that comes from an apple on the edge of the picture physically came from that apple. It can&#039;t be magically converted into light that came from an orange in the center of the picture.  No matter what you do, if you want that photon, you&#039;ve got to use it to show the apple. If you don&#039;t show the apple, you don&#039;t get to use that photon.</description>
		<content:encoded><![CDATA[<p>Ok.. I&#8217;m back (sorry <img src='http://www.stevehuffphoto.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> ).  Jerry, yes you will get the same exposure with the same ISO and settings.  Of course.  That&#8217;s because ISO in a digital calibrated for a particular camera to produce the right exposure at the right ISO.  The sunny 16 rule should always work.  ISO 100 **IS DEFINED** for any camera as WHATEVER sensor gain makes sunny 16 work for that camera.  That doesn&#8217;t mean it uses the same amount of light from one camera to another.  That just means it&#8217;s the gain correction needed to compensate for whatever amount light sunny 16 happens to be on that camera. That IS ISO 100.  In a cropped camera that happens to be a higher gain, because there is less light.  And thus it happens to produce more noise too.    I don&#8217;t care what argument you make, you can&#8217;t get around the fact, that the focal plane is where it is (unless you mess up infinity focus); the image size on that plane is what it is, ALWAYS for any given lens.  You either accept the whole image and all the light in it, or you crop that image and only accept part of it and part of the light in it.  Nobody has answered me, where did the light from the rest of the image go?  </p>
<p>Light that comes from an apple on the edge of the picture physically came from that apple. It can&#8217;t be magically converted into light that came from an orange in the center of the picture.  No matter what you do, if you want that photon, you&#8217;ve got to use it to show the apple. If you don&#8217;t show the apple, you don&#8217;t get to use that photon.</p>
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		<title>By: Jerry_R</title>
		<link>http://www.stevehuffphoto.com/2010/02/07/the-bokeh-files-featuring-the-leica-m9-olympus-e-p2/#comment-4093</link>
		<dc:creator>Jerry_R</dc:creator>
		<pubDate>Mon, 15 Mar 2010 11:19:01 +0000</pubDate>
		<guid isPermaLink="false">http://www.stevehuffphoto.com/?p=4727#comment-4093</guid>
		<description>Of course I meant 100mm, not 10mm.</description>
		<content:encoded><![CDATA[<p>Of course I meant 100mm, not 10mm.</p>
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